Hi,
VM word length famously follows binomial distribution of f(n, 9, 0.5) + 1. i.e. expected number of heads when you toss coin 9 times plus 1.
I suspect that what ever encoding scribes used for the text, the word length is independent variable and it was produced with dices.
Method is pretty simple. Throw 3 dices, sum the eyes and divide by two rounding up. Use the result as word length and you get basically the same distribution as VM has.
Dices were well known at the time and this is easy and accessible method to get a random number for the word length while maintaining desired average number of 5 to 6 glyphs.
Pictured my dices.
VM word length famously follows binomial distribution of f(n, 9, 0.5) + 1. i.e. expected number of heads when you toss coin 9 times plus 1.
I suspect that what ever encoding scribes used for the text, the word length is independent variable and it was produced with dices.
Method is pretty simple. Throw 3 dices, sum the eyes and divide by two rounding up. Use the result as word length and you get basically the same distribution as VM has.
Dices were well known at the time and this is easy and accessible method to get a random number for the word length while maintaining desired average number of 5 to 6 glyphs.
Pictured my dices.
![[+]](https://www.voynich.ninja/images/collapse_collapsed.png)
